Summary of Ecuación de una circunfunferencia dados 3 puntos │ método por mediatrices

00:00:00 - 00:20:00

In this video, Martin demonstrates how to calculate the equation of a circle using mediatrices. First, he shows how to find the ordinary and general equation of a circle passing through three points (a, b, and c). Next, he shows how to find the center of a circle by finding the intersection of two intersecting lines. Finally, he provides an example of how to calculate the radius and center of a circle using these coordinates.

• 00:00:00 In this video, Martin demonstrates how to calculate the equation of a circle using mediatrices. First, subscribers should subscribe to his channel to continue seeing videos like this one. Then, using the three points (a, b, and c), he demonstrates how to find the ordinary and general equation of a circle passing through these points. Next, he shows how to find the center of a circle by finding the intersection of two intersecting lines. Finally, he provides an example of how to calculate the radius and center of a circle using these coordinates.
• 00:05:00 The author explains how to calculate the equation of a circumference given three points. They need to know a point on the circumference that is already known, and that belongs to bean per se. They also need to know the slope of the line segment connecting the point and bea, and so the angle formed by these lines is 90 degrees. To find the pendiente of the media triz, they first need to find the pendiente of the recta perpendicular to the recta abc, which is given by the equation point Pendiente de la media triz = Point medio + Pendiente de la recta perpendicular a la recta abc. They then proceed to find the pendiente of bc, which would be given by the equation Pendiente de la media triz = 2 (Point medio - Point abc) + 1. Simplifying these equations yields the final equation for the media triz: Pendiente de la media triz = 2 (Point medio - Point abc) + 1. This dark area on the graph is the pendiente of the recta media triz.
• 00:10:00 The author explains how to solve an equation for a circunfunference given three points. The equation is x-4y=23, where x and y are the coordinates of the first and third points, respectively. The equation is solved by subtracting 4y from x-4 and thenmultiplying by 2. This leaves x+4 as the solution. The author then explains a method for solving systems of two equations in one, using the principle of substitution.
• 00:15:00 This video simplifies the calculation of a circumferential coordinate given three points. It also shows how to simplify the equation to 2 less 2 equals 0, which cancels out and yields the equation sought. This is 8 - 2 which is 4, which is the exponent needed to solve for x. x is then found by solving 4 equations for x, each with a different exponents, and taking the square root of the result. The final equation is x = 17.5 between the two points, which is the center of the circumferential circle or the intersection of two circumferential circles.
• 00:20:00 The video discusses how to solve a simple conic equation, given three points. The equation can be solved using the method of mediators, which is a faster way than using the standard square root method. First, the equation is solved for the greatest point, and then the double product of this value and the second point is solved. This process is repeated until the equation is solved for all points. Once this is done, the regular equation can be solved using the arctangent function. This final equation will equal zero at the three points, and the video explains how to find the constants in the equation.