Summary of Movimiento Rectilíneo Uniforme (MRU) - Ejercicios Resueltos - Nivel 2

00:00:00 - 00:25:00

The YouTube video "Movimiento Rectilíneo Uniforme (MRU) - Ejercicios Resueltos - Nivel 2" presents several solved exercises on Uniform Rectilinear Movement (MRU). The problems involve calculating the time and distance covered by two objects moving in opposite directions with constant velocities to meet each other or by two objects moving in the same direction with different velocities. The video provides formulas for calculating the distance covered and the time taken, which can either be solved using a graphical method or directly using the formula. The lesson concludes by encouraging viewers to subscribe and continue learning about physics.

• 00:00:00 In this section, the YouTuber goes through an example problem of calculating the time it takes for two objects, Mario and Luigi, moving in opposite directions with constant velocities to meet each other. The problem is presented with a graph that shows the initial separation of the objects, 300 meters apart, and their velocities, 10 and 5 meters per second respectively. The YouTuber explains that the time it takes for the objects to meet is the same for both, so the problem only requires finding the distance that Mario travels until they meet. This is done using the formula distance equals velocity times time, where the velocity is Mario's velocity, which is 10 meters per second.
• 00:05:00 In this section, the video presents a solved exercise on Uniform Rectilinear Movement (MRU). The exercise involves calculating the time and distance covered by Luigi, who moves at a speed of 5 meters per second to the left. The distance between Mario and Luigi at the start is 300 meters. By equating the distance traveled by Luigi to the distance between Mario and Luigi, the video shows how to calculate the time required for the two to meet. The answer is then converted to seconds, the standard unit for time.
• 00:10:00 In this section, the video presents two exercises solved using the formula for time of encounter between two objects moving in opposite directions at a constant speed. In the first example, two characters, Mario and Luigi, are initially separated by 300 meters and start moving towards each other at 10 and 5 meters per second, respectively. The video also shows how to solve another problem, calculating the time it takes for a police car to catch a dinosaur, both moving in the same direction, with different speeds.
• 00:15:00 In this section, the video presents an exercise where a police car chases a dinosaur and a stopwatch is used to measure the time elapsed. The distance is measured in meters, and the police car's speed is measured in meters per second, while the dinosaur's speed is measured in kilometers per hour, thus requiring a conversion into meters per second. The distance traveled by the police car is calculated using the formula distance = speed x time, where the police car's speed is given as 12 meters per second. The distance covered by the dinosaur is also calculated using the distance formula, where the dinosaur's speed is given as 10 meters per second, and the time taken is calculated using the time elapsed on the stopwatch.
• 00:20:00 In this section, the video solves a problem involving two mobiles moving in the same direction with MRU. The distance covered by the first mobile, a dinosaur, is calculated, and the time it takes for a police car to reach the dinosaur is determined using the formula for time of approach. The video also demonstrates how to find the time of approach from the formula, which is the initial separation distance divided by the difference in the speed of the two mobiles, provided the faster mobile speed is greater than the slower one.
• 00:25:00 In this section, the speaker demonstrates a different method of calculating the time of encounter in a constant velocity scenario by using the formula of distance divided by the difference in velocity. He explains that the initial distance, represented as "d" in the formula, is the separation distance between the two moving objects at the start of the problem. Users may either use this method or a graphical representation known as the "triangulito" to solve problems of this nature, or they may refer to the formula for faster resolution. The lesson concludes by encouraging viewers to subscribe and continue learning about physics.